I have a long RegEx that is working, but I have a section at the end that is perplexing me. I have a scenario where I am parsing some HTML and one of two scenarios can happen. Either the pattern I am searching for ends with a X followed immediately by a single digit or it’s a . Here’s the RegEx fragment:
(X(\d+)| )
As you might have noticed, I don’t care about the X or the , I just want to capture the digit if it’s there. It appears that in order to use the |, I have to use a capture group. So now I get BOTH X5 AND 5 if that pattern exists. I really just want the digit captured if it’s there.
Thanks!
To get the effect of grouping, without the effect of capturing, use the
(?:...)notation:This is equivalent to what you wrote, except that it doesn’t create a capture group for
X5, only for5.(By the way, you say “a single digit”, but your regex has
\d+rather than\d, so it can actually match multiple digits.)