Question

I have a long string that contains information like this:

|infoId-*-info||infoId-*-info||infoId-*-info| ...

I use the '-*-' character as seperator and I want to make searching just on right side of '-*-' character but it should return whole part of infoId-*-info if it match any info , is there anyway to do that?

Thanks in advance

Example:

This is my String :

|8d9f9a0g9r8ad8f-*-sedat||0sdf7a89s9d0wg-*-derya||9g7a6w6e7d89awwe-*-caner|

for this string if my search value is "edat" how can I return whole 8d9f9a0g9r8ad8f-*-sedat string, and if my search value is "s" it shouldnt return also 0sdf7a89s9d0wg-*-derya because of left side of "-*-" contains "s" character.
If u can give me jsfiddle link that supports this example it will be very wellcomed thanks so much for spending time.

Answer 1

Sounds like you need something along the lines of

/((?:infoId)\/YOUR_REGEX_FOR_INFO)\s/

(we don’t know how your infoId and info are structured).

EDIT following the example added by OP

You can use (for edat):

/\|([^-]+-\*-[^|]*edat[^|]*\|/

I don’t know which language you are using but you can use the “global” flag to get all matches in the string at once. If it’s JS, it will be /\|([^-]+-\*-[^|]*edat[^|]*\|/g.