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Home/ Questions/Q 8851393
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T13:08:42+00:00 2026-06-14T13:08:42+00:00

I have a loop: (defun echo-lines () (loop while (let ((line (read-line))) (if (equal

  • 0

I have a loop:

(defun echo-lines ()
  (loop while 
        (let ((line (read-line)))
           (if (equal line "done")
               nil
               (print line)))))

I expect it to echo the user’s input after they end the line, unless they have typed “done”, in which case it stops. Instead, it echos a blank line the first time, after that, it echos the input from one previous.
Example:

* (echo-lines)
Hello, loop.

This is my second line.
"Hello, loop." 
This is my third.
"This is my second line." 
I'm almost done.
"This is my third." 
done
"I'm almost done." 
NIL

Expected:

* (echo lines)
Hello, loop.
"Hello, loop."
done
NIL
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T13:08:43+00:00Added an answer on June 14, 2026 at 1:08 pm

    The effect is caused by a mix of buffered output and the definition of PRINT.

    PRINT does not cause output to be written immediately if the underlying output stream is buffered. Note also that PRINT prints the newline first. Note that for portable code you should assume that an output stream is buffered. This means that you need to make sure that buffered output is written when you need it. Use FORCE-OUTPUT (doesn’t wait) and FINISH-OUTPUT (waits).

    This is a slightly rewritten version.

    (defun echo-lines ()
      (loop for line = (read-line)
            until (equal line "done")
            do
            (write-line line)
            (finish-output)))
    
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