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Home/ Questions/Q 7601973
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T23:17:41+00:00 2026-05-30T23:17:41+00:00

I have a MainActivity and an AsyncTask MyTask. They are separate classes. In MyTask,

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I have a MainActivity and an AsyncTask MyTask. They are separate classes. In MyTask, I want to update a TextView in MainActivity.

This seems easy if MyTask in a inner class of MainActivity because I can just call findViewById(). But now these two classes are separate.

So in my MainActivity I do this:

MyTask myTask=new MyTask();
Context context=this.getApplicationContext();
myTask.execute(context);

And my task is like this:

public class MyTask extends AsyncTask<Context, Void, Void>
{
    TextView mText;
    protected Void doInBackground(Context... params) {
        Context context=params[0];
        mText = (TextView) ((MainActivity)context).findViewById(R.id.text);
...
    }
}

I know the “mText = (TextView) ((MainActivity)context).findViewById(R.id.text);” is wrong but I haven’t found the solution.

Any Hints

Thanks in Advance

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  1. Editorial Team
    Editorial Team
    2026-05-30T23:17:43+00:00Added an answer on May 30, 2026 at 11:17 pm

    You can do something like this. You can ignore the WeakReference if the task won’t be long living:

    public class MyTask extends AsyncTask<Void, Void, Void> {
      private WeakReference<MainActivity> mActivity;
      public MyTask(MainActivity activity) {
        mActivity = new WeakReference<MainActivity>(activity);
      }
    
      public void onPostExecute(Void result) {
        MainActivity activity = mActivity.get();
        if (activity != null) {
          TextView text = activity.findViewById(R.id.text);
        }
      }
    }
    
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