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Home/ Questions/Q 1069531
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T20:26:01+00:00 2026-05-16T20:26:01+00:00

I have a map, let’s call it M, which contains data mapped through N

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I have a map, let’s call it M, which contains data mapped through N dimensions.

# If it was a 2d map, I could iterate it thusly:
start, size = (10, 10), (3, 3)
for x in range(start[0], start[0]+size[0]):
    for y in range(start[1], start[1]+size[1]):
        M.get((x, y))
# A 3d map would add a for z in ... and access it thusly
M.get((x, y, z))
# And so on.

My question is: How do I make an iterator that can yield the correct iteration sequence? That is, given start, size = (10, 10), (3, 3) it would yield the 2-tuple sequence (10, 10), (10, 11), (10, 12), (11, 10), (11, 11) etc. And given start, size = (10, 10, 10), (3, 3, 3) it would yield the correct 3-tuple sequence.

Yeah, I tried myself, but my head exploded. Or I can’t justify spending time figuring it out, even though it’s fun. Take your pick 🙂

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  1. Editorial Team
    Editorial Team
    2026-05-16T20:26:01+00:00Added an answer on May 16, 2026 at 8:26 pm

    In Python 2.6+:

    itertools.product(*[xrange(i, i+j) for i,j in zip(start, size)])
    
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