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Home/ Questions/Q 6627263
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T21:59:32+00:00 2026-05-25T21:59:32+00:00

I have a mapped superclass with two already indexed properties. now i want to

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I have a mapped superclass with two already indexed properties. now i want to create a group index over both properties. until now it worked with:

@MappedSuperclass
Class A {
    @Index(name="pa")
    int a;
    @Index(name="pb")
    int b;
}

According to the hibernate documentation i could annotate my new index with @Table (hibernate annotation). but i dont know what to set for the required appliesTo parameter.

has anybody tried this successfully before?

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  1. Editorial Team
    Editorial Team
    2026-05-25T21:59:33+00:00Added an answer on May 25, 2026 at 9:59 pm

    From Hibernate Documentation:

    @Table(appliesTo=”tableName”, indexes = { @Index(name=”index1″,
    columnNames={“column1”, “column2”} ) } ) creates the defined indexes
    on the columns of table tableName. This can be applied on the primary
    table or any secondary table.

    Update:
    For the @MappedSuperclass you could try to use @Tables annotation

    @Tables(value={@Table(appliesTo="table1", indexes={@Index(name="index1", columnNames={"column1", "column2"})}),  
                   @Table(appliesTo="table2", indexes={@Index(name="index1", columnNames={"column1", "column2"})})})
    

    But that seems rather tedious.
    Note that, @Index annotation has columnNames property, which allows you to specify more than one column. However, I’m not sure whether you should duplicate index definition for each field.

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