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Home/ Questions/Q 963395
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T01:39:52+00:00 2026-05-16T01:39:52+00:00

I have a mdicontainer form that summons forms. My problem is when the a

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I have a mdicontainer form that summons forms. My problem is when the a user clicks again the menu for that form, it also make another instance of it.

What I did is declare a public class with a public variable on it ex: Boolean isFormOneOpen = false. Then every time formOne opens, it checks first the global variable I declared a while ago if it’s false, if it is, instantiate an object of a formOne and then show it. Otherwise, do nothing. Very static, imagine if I have many forms, I have to declare a variable for each form to check if it’s already open. Can you provide me a solution for this? Maybe a method that accepts a Form? Or any more clever way to do this.

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  1. Editorial Team
    Editorial Team
    2026-05-16T01:39:53+00:00Added an answer on May 16, 2026 at 1:39 am

    You don’t need a variable, you could iterate the MdiChildren collection to see if the form is already opened. For example:

    Private Sub btnViewChild_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnViewChild.Click
        For Each child In Me.MdiChildren
            If TypeOf child Is Form2 Then
                child.WindowState = FormWindowState.Normal
                child.Focus()
                Exit sub
            End If
        Next
        Dim frm As New Form2
        frm.MdiParent = Me
        frm.Show()
    End Sub
    

    The VB.NET-centric solution:

    Private Sub btnViewChild_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnViewChild.Click
        Form2.MdiParent = Me
        Form2.WindowState = FormWindowState.Normal
        Form2.Show
    End Sub
    
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