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Home/ Questions/Q 6771247
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T15:24:34+00:00 2026-05-26T15:24:34+00:00

I have a member function which takes a constant reference parameter to another object.

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I have a member function which takes a constant reference parameter to another object. I want to const_cast this parameter in order to easily use it inside the member function. For this purpose, which of the following codes is better?:

void AClass::AMember(const BClass & _BObject)
{
    // FORM #1 - Cast as an object:
    BClass BObject = const_cast<BClass &>(_BObject);
    // ...
}

void AClass::AMember(const BClass & _BObject)
{
    // FORM #2 - Cast as a reference:
    BClass & BObject = const_cast<BClass &>(_BObject);
    // ...
}

Can you please compare these two forms? Which one is better in criteria of speed and memory usage?

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  1. Editorial Team
    Editorial Team
    2026-05-26T15:24:35+00:00Added an answer on May 26, 2026 at 3:24 pm

    The first version makes a copy of the object. The second version doesn’t. So the second version will be faster unless you want to make a copy.

    By the way, all identifiers that start with an underscore followed by a capital letter are reserved for use by the compiler. You should not be using variable names like _BObject.

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