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Editorial Team
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Asked: 2026-06-10T15:58:46+00:00

I have a menu that appears on all my pages. It contains php for

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I have a menu that appears on all my pages. It contains php for passing filenames to url’s as follows. Here is a snippet…

document.write('<li><a href="somefile.php?folder=<?php echo "_abc"; ?>">abc</a></li>');
document.write('<li><a href="somefile.php?folder=<?php echo "_def"; ?>">def</a></li>');
document.write('<li><a href="somefile.php?folder=<?php echo "_ghi"; ?>">ghi</a></li>');

It includes css and that works fine.
I have saved the menu as a seperate .js file and used…

<script src="js/menucss.js"></script>

…to load it from each page that I want it to appear. The menu displays and the css works fine – however the php does not parse and the page shows the php markup. What am I doing wrong?

Thanks in advance.
Neil

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1 Answer

  1. Editorial Team

    You shouldn’t do it like that.

    Have a page called menu.php saved somewhere, which includes:

    <ul>

    <li><a href="somefile.php?folder=<?php echo "_abc"; ?>">abc</a></li>
    <li><a href="somefile.php?folder=<?php echo "_def"; ?>">def</a></li>
    <li><a href="somefile.php?folder=<?php echo "_ghi"; ?>">ghi</a></li>

</ul>

    Then include it, on the server side (index.php):

    <html>
<head>
    <title></title>
</head>
<body>
<header>
    <?php include("main.php"); ?>
</header>
</body>
</html>

    This approach is far superior:

    • It does not require an extra request to get the data.
    • There will be no flickering or awkward moments of data loading, the menu would appear as if you’ve coded it directly into the page.
    • It’s much faster.
    • It doesn’t use JavaScript, which the client can choose to disable.
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