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Home/ Questions/Q 6094245
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T12:39:17+00:00 2026-05-23T12:39:17+00:00

I have a MessageThread entity which contains Message entities. The foreign key is set

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I have a MessageThread entity which contains Message entities. The foreign key is set up so I can navigate from MessageThread to all the messages easily. Each message has a from and to address. I want to write a query to retrieve all message threads for which a particular address has either written or received a message.

MessageThread
{
    EntityCollection<Message> messages;
}

Message
{
    long FromAccount;
    long ToAccount;
}

The query should be something like this, but I can’t figure out how to navigate to the To and From addresses all the way from the MessageThread class.

public IQueryable<MessageThread> GetMessageThreads(long userAccount)
{
    return from messageThread in this.ObjectContext.MessageThreads
           where messageThread.Messages.ToAddress == userAccount || 
                 messageThread.Messages.FromAddress == userAccount
           select messageThread;
}

That query won’t work because messageThread.Messages is a collection and both ToAddress and FromAddress are not directly accessible from the collection.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T12:39:18+00:00Added an answer on May 23, 2026 at 12:39 pm

    Select the child items first and then include the parent. Then at the end, just select a list of the parent entity that you were after.

    Messages.Include("MessageThread")
            .Where(m => m.FromAccount == userAccount
                     || m.ToAccount == userAccount)
            .Select(m => m.MessageThread)
    

    If you leave the select off the end you get a list of messages with the parents included. It depends on what you where after.

    OR…. (this, which is a bit neater)

    MessageThreads.Where(s => s.Messages.Any( m => m.FromAccount == userAccount
                                                || m.ToAccount == userAccount))
    
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