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Home/ Questions/Q 4107016
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T21:27:02+00:00 2026-05-20T21:27:02+00:00

I have a method: expect(processor.process(arg1, list)); expectLastCall().anyTImes(); Now, I need the list to contain

  • 0

I have a method:

expect(processor.process(arg1, list));
expectLastCall().anyTImes();

Now, I need the list to contain certain values. And the problem is that the values have to be added to the list in a right order, otherwise the list won’t equal the real list. So I cannot just make a new list and add values into it, because if method process changed order of adding values into the list, the test would fail.
I tried this

List list=createMock(List.class);
expect(list.add(value1)).andReturn(true);
expect(lst.add(value2)).andReturn(true);

but he gives this exception:

java.lang.AssertionError: 
  Unexpected method call process(arg, [Listvalue1,Listvalue2]):
    process(arg, EasyMock for interface java.util.List): expected: 1, actual: 0

Thanks a lot.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T21:27:03+00:00Added an answer on May 20, 2026 at 9:27 pm

    You could use IAnswer and EasyMock.getCurrentArguments() and then manually assert the contents of the list

    expect(processor.process(arg1, list));
    expectLastCall().anyTimes().andAnswer(new IAnswer<Object>() {
        public Object answer() throws Throwable {
            List myList = (List) EasyMock.getCurrentArguments()[1];
            // do your assertions on the list here (or change the order as required)
        }    
    });
    

    A big drawback of using EasyMock.getCurrentArguments() is that it is not “refactor-safe” (If you change the order of the parameters it will break the test).

    Hope it helps.

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