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Home/ Questions/Q 9215153
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T02:08:25+00:00 2026-06-18T02:08:25+00:00

I have a method findByProperties(Parameter… p); so it can take any number of parameters.

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I have a method findByProperties(Parameter… p); so it can take any number of parameters. But what I am confused is if I had to call this method and I do not know the number of parameters how do I do that

suppose I have a list with parameters, and the size of the list changes each time you call the method, the how would I add the parameters from the list to the method call?

for(ArrayList<Parameter> p : list){
   findByProperties(p);  //not sure what to do here
 }

EDIT:

this was the solution:

Parameter[] paramArray = new ArrayList<Parameter>().toArray(new Parameter[]{});
findByProperties(paramArray);
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  1. Editorial Team
    Editorial Team
    2026-06-18T02:08:27+00:00Added an answer on June 18, 2026 at 2:08 am

    You can do something like this:

    Parameter[] paramArray = new ArrayList<Parameter>().toArray(new Parameter[]{});
    findByProperties(paramArray);
    

    It’s the same as something like:

    findProperties(param1, param2);
    

    Because Java internally transforms a varargs-list into an array, so you can pass an array, too.

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