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Home/ Questions/Q 786001
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T20:58:05+00:00 2026-05-14T20:58:05+00:00

I have a method for reading JSON from a service, I’m using Gson to

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I have a method for reading JSON from a service, I’m using Gson to do my serialization and have written the following method using type parameters.

public T getDeserializedJSON(Class<T> aClass,String url)
{
    Reader r = getJSONDataAsReader(url);
    Gson gson = new Gson();
    return gson.fromJson(r, aClass);
}

I’m consuming json which returns just an array of a type e.g.

[
 { "prop":"value" }
 { "prop":"value" }
]

I have a java class which maps to this object let’s call it MyClass. However to use my method I need to do this:

RestClient<ArrayList<MyClass>> restClient = new RestClient<ArrayList<MyClass>>();
ArrayList<MyClass> results = restClient.getDeserializedJSON(ArrayList<MyClass>.class, url);

However, I can’t figure out the syntax to do it. Passing just ArrayList.class doesn’t work.

So is there a way I can get rid of the Class parameter or how do I get the class of the ArrayList of MyClass?

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  1. Editorial Team
    Editorial Team
    2026-05-14T20:58:06+00:00Added an answer on May 14, 2026 at 8:58 pm

    You can use Bozho’s solution, or avoid the creation of a temporary array list by using:

    Class<List<MyClass>> clazz = (Class) List.class;
    

    The only problem with this solution is that you have to suppress the unchecked warning with @SuppressWarnings("unchecked").

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