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Home/ Questions/Q 8843099
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T11:08:01+00:00 2026-06-14T11:08:01+00:00

I have a method in Objective-c that takes in an NSDictionary and returns the

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I have a method in Objective-c that takes in an NSDictionary and returns the values as a space-separated NSString. This application is cross-platform, and as such I cannot use fast enumeration. This is what I have so far, followed by the output (which shows that the String is never created):

-(NSString *)stringValuesFromDict:(NSDictionary *map)
{
    NSArray *values = [map allValues];
    NSString *params = [NSString string];
    NSLog(@"values length: %d", [values count]);
    NSLog(@"values = %@", [values description]);
    for (int i = 0; i < [values count]; i++)
    {
        [params stringByAppendingString:[values objectAtIndex:i]];
        [params stringByAppendingString:@" "];
    }
    NSLog(@"params = %@", params);
    return params;
}

The NSDictionary:

{"arg1"="monkey"}

The output:

values length: 1
values = (
    monkey
)
params = 

What am I doing wrong? How can I get params to be set to monkey?

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  1. Editorial Team
    Editorial Team
    2026-06-14T11:08:02+00:00Added an answer on June 14, 2026 at 11:08 am

    You need a mutable string. Change this:

    NSString *params = [NSString string];
    

    to this:

    NSMutableString *params = [NSMutableString string];
    

    Then change these:

    [params stringByAppendingString:[values objectAtIndex:i]];
    [params stringByAppendingString:@" "];
    

    to these:

    [params appendString:[values objectAtIndex:i]];
    [params appendString:@" "];
    
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