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Home/ Questions/Q 843667
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T06:09:53+00:00 2026-05-15T06:09:53+00:00

I have a method that receives messages from a queue of msmq. I have

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I have a method that receives messages from a queue of msmq.

I have 6 different queues in msmq and i d like a single generic method that would receive the messages. THis work, but i need to write 6 methods for each queue. I d like to make it more generic.

public List<QueMessage> getMessagesFromObj1Queue()
{
    List<QueMessage> messageList = new List<QueMessage>();

    QueObj1 que = new QueObj1();

    while (que.ReceiveAll().Count > 0)
    {
        varmessage = que.Receive(new TimeSpan(0, 1, 0));
        messageList.Add(message);
    }

    return messageList;
}

I have 5 different object which just extends a single abstract class. Below doenst work.

public List<QueMessage> getMessagesFromObj1Queue<T>(T que)
{
    List<QueMessage> messageList = new List<QueMessage>();

    while (que.ReceiveAll().Count > 0)
    {
        varmessage = que.Receive(new TimeSpan(0, 1, 0));
        messageList.Add(message);
    }

    return messageList;
}

Above doesnt work

how to fix this?

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  1. Editorial Team
    Editorial Team
    2026-05-15T06:09:54+00:00Added an answer on May 15, 2026 at 6:09 am

    If T in your example is some base class that all queue objects inherit, then you can just pass that to the method instead of T:

    public List<QueMessage> getMessagesFromObj1Queue<T>(QueueObjBase que) { ... }
    

    Otherwise, if there’s come common interface that all T‘s will implement, use that as a generic constraint:

    public List<QueMessage> getMessagesFromObj1Queue<T>(T que) 
       where T : [yourInterface]
    {
    }
    

    Without a generic constraint on T, the compiler doesn’t have any information to know what method or properties are available, and so can only treat T as object – which, of course, doesn’t have a RecieveAll() method.

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