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Home/ Questions/Q 8809533
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T02:53:57+00:00 2026-06-14T02:53:57+00:00

I have a method which looks like this: def order_by(*args): print list(args) Is there

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I have a method which looks like this:

def order_by(*args):
    print list(args)

Is there a way I could pass a list of three items and have each item in the list passed as an individual parameters?

params = ['a', 'b', 'c']

would equate to

order_by('a', 'b', 'c')

Any ideas?

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  1. Editorial Team
    Editorial Team
    2026-06-14T02:53:58+00:00Added an answer on June 14, 2026 at 2:53 am

    The *arguments syntax can be used for calling functions too, provided params is an iterable:

    order_by(*params)
    

    See the calls syntax specification.

    For an actual dictionary, use the **kwargs syntax:

    params = dict(a='a', b='b', c='c')
    somemethod(**params)
    

    where somemethod accepts a, b and c arguments or has a **kw catch-all argument. Note that **params does not work if all your function defines is a *args positional argument catch-all.

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