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Home/ Questions/Q 8042463
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T04:35:14+00:00 2026-06-05T04:35:14+00:00

I have a method which looks like this: void foo (List<String> list, …) {

  • 0

I have a method which looks like this:

void foo (List<String> list, ...) {
  ...
  for (String s : list) { // this is the only place where `list` is used
    ...
  }
  ...
}

the exact same code would work if I replace List<String> list with String[] list, however, to avoid spaghetti code, I keep the single method, and when I need to call it on an array a, I do it like this: foo(Arrays.asList(a)).

I wonder if this is The Right Way.

Specifically,

  • What is the overhead of Arrays.asList()?
  • Is there a way to write a method which would accept both arrays and lists, just like the for loop does?

Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T04:35:15+00:00Added an answer on June 5, 2026 at 4:35 am

    Arrays.asList() has a small overhead. There is no real way to implement one method for both List and arrays.

    But you can do the following:

    void foo (List<String> list, ...) {
      ...
      for (String s : list) { // this is the only place where *list* is used
        ...
      }
      ...
    }
    
    void foo (String[] arr, ...) {
      if ( arr != null ) {
          foo(Arrays.asList(arr),...);
      }
    }
    
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