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Home/ Questions/Q 673171
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T00:33:58+00:00 2026-05-14T00:33:58+00:00

I have a method which returns some xml in a memory stream private MemoryStream

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I have a method which returns some xml in a memory stream

private MemoryStream GetXml()
{
    XmlWriterSettings settings = new XmlWriterSettings();
    settings.Indent = true;

    using (MemoryStream memoryStream = new MemoryStream())
    {
        using (XmlWriter writer = XmlWriter.Create(memoryStream, settings))
        {
            writer.WriteStartDocument();
            writer.WriteStartElement("root");
            writer.WriteStartElement("element");
            writer.WriteString("content");
            writer.WriteEndElement();
            writer.WriteEndElement();
            writer.WriteEndDocument();
            writer.Flush();
        }

        return memoryStream;
    }
}

In this example the format of the xml will be:

<?xml version="1.0" encoding="utf-8"?>
<root>
  <element>content</element>
</root>

How can I insert a new element under the root e.g.:

<?xml version="1.0" encoding="utf-8"?>
<root>
  <element>content</element>
  ----->New element here <------
</root>

EDIT:

Also please suggest the most efficient method as returning a MemoryStream may not be the best solution.

The final xml will be passed to a custom HttpHandler so what are the best options for writing the output?

context.Response.Write vs context.Response.OutputStream

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T00:33:59+00:00Added an answer on May 14, 2026 at 12:33 am

    Your first issue is that you don’t have XML – you have a stream of bytes which can be loaded into an XDocument or XmlDocument. Do you really need to output to a stream instead of directly into an XML Document?

    BTW, I think you need to lose the using block around the MemoryStream. You won’t be able to use the stream for much after it’s been disposed.

    public void AppendElement()
    {
        XDocument doc;
        using(MemoryStream stream = GetXml())
        {
            using(var sr = new StreamReader(stream))
            {
                doc = XDocument.Load(sr);
            }
        }
        if(doc.Root != null)
        {
            doc.Root.Add(new XElement("Whatever"));
        }
    }
    
    private static MemoryStream GetXml()
    {
        var settings = new XmlWriterSettings {Indent = true};
    
        var memoryStream = new MemoryStream();
        using (XmlWriter writer = XmlWriter.Create(memoryStream, settings))
        {
            writer.WriteStartDocument();
            writer.WriteStartElement("root");
            writer.WriteStartElement("element");
            writer.WriteString("content");
            writer.WriteEndElement();
            writer.WriteEndElement();
            writer.WriteEndDocument();
            writer.Flush();
        }
    
        return memoryStream;
    }
    

    For efficiency, try to work directly with XDocument. You seem to want to use XmlWriter, so here’s how to do it (not tested):

    public void AppendElement()
    {
        XDocument doc = GetXml();
        if(doc.Root != null)
        {
            doc.Root.Add(new XElement("Whatever"));
        }
    }
    
    private static XDocument GetXml()
    {
        var doc = new XDocument();
    
        using (XmlWriter writer = doc.CreateWriter())
        {
            writer.WriteStartDocument();
            writer.WriteStartElement("root");
            writer.WriteStartElement("element");
            writer.WriteString("content");
            writer.WriteEndElement();
            writer.WriteEndElement();
            writer.WriteEndDocument();
            writer.Flush();
        }
    
        return doc;
    }
    

    Update:

    You can write the XML with

    doc.Save(HttpContext.Response.Output);
    

    Again, I can’t test it now, but try this:

    private static XDocument GetXml()
    {
        return new XDocument(
            new XElement(
                "root", 
                new XElement(
                    "element", 
                    "content")));
    }
    
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