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Home/ Questions/Q 8684661
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T22:21:51+00:00 2026-06-12T22:21:51+00:00

I have a method, which simplified looks like this: class Foo { public function

  • 0

I have a method, which simplified looks like this:

class Foo {

   public function bar($id) {
      // do stuff using $this, error occurs here
   }

}

Calling it like this works great:

$foo = new Foo();
$foo->bar(1);

However, if I call it using call_user_func_array(), like this:

call_user_func_array(array("Foo", "bar"), array('id' => 1));

Which should be equal, I get the following error:

Fatal error: Using $this when not in object context in

($this is undefined)

Why is this? Is there something I am missing? How should I do this so I still can use $this in the called method?

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  1. Editorial Team
    Editorial Team
    2026-06-12T22:21:52+00:00Added an answer on June 12, 2026 at 10:21 pm

    array("Foo", "bar") is equal to Foo::bar(), i.e. a static method – this makes sense since $foo is nowhere used and thus PHP cannot know which instance to use.

    What you want is array($foo, "bar") to call the instance method.

    See http://php.net/manual/en/language.types.callable.php for a list of the various callables.


    You also need to pass the arguments as an indexed array instead of an associative array, i.e. array(1) instead of array('id' => 1)

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