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Home/ Questions/Q 8108983
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T01:16:41+00:00 2026-06-06T01:16:41+00:00

I have a modal window that uploads files to server. Works great. Upon completion

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I have a modal window that uploads files to server. Works great. Upon completion of the upload I am refreshing a div on the parent page. Almost works. What I need in order for it to work is to be able to grab $_GET[‘edit’]. Hopefully my layout of the code will help show my issue.

Modal Window: upload complete

$('#albumFinished').click(function() {
       $('#sortableImages').load('../includes/sortImages.php');
 });

sortImages.php

$galleryID = $_SESSION['newGalleryId'];
$getGalleryID = $_GET['edit']; 

echo "<ul>";

    while($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
       $sortImageName = $row['OrgImageName']; 
       $sortPath = "../data/gallery/" . $getGalleryID . "/images/album/" . $sortImageName;
                    echo "<li class='sortPhotos' id='recordsArray_{$row['id']}' >";
                    echo '<img src="'. $sortPath .'"/>';
                    echo "</li>";
                }

    echo "</ul>";

Everything is functioning properly except I am unable to grab the $_GET variable. How do I go about grabbing this variable? Also if my explanation is not clear, I will try to clarify further.

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  1. Editorial Team
    Editorial Team
    2026-06-06T01:16:44+00:00Added an answer on June 6, 2026 at 1:16 am

    I’m sorry maybe I’m not understanding but your not actually sending any data to the sort images.php to get with $_get your simply doing a load which is identical to just typing that url in your browser

    try using $.post or $.get or $.ajax to send your get info over similar to this

    $.get("../includes/sortImages.php", { edit: "what your editing"},
       function(data){
         return your data here
       });
    
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