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Home/ Questions/Q 4625698
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T03:18:37+00:00 2026-05-22T03:18:37+00:00

I have a model called Metadatum (silly, I know) which has two fields, key

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I have a model called Metadatum (silly, I know) which has two fields, key and value. A key is prefixed with it’s type followed by an underscore. The possible types are modifier_, option_ or uom_ (unit of measure) which is then followed by a user-defined key. For example: uom_ounce.

I define the types in a class method of Metadatum:

def self.types
    { 'Modifier' => 'modifier', 'Option' => 'option', 'Unit of Measure' => 'uom'}
end

I parse out my static types from the user-defined keys using this instance method:

def parsed_key
    self.key.split('_', 2).last
end

My goal is to present a select box for each type. Here’s how I’m trying to do accomplish it:

<% Metadatum.types.each do |type| %>
    <%= f.fields_for :item_metadata do |builder| %>
        <%= cell((builder.label :fk_metadatum_id, type.first),   (builder.collection_select(:fk_metadatum_id, Metadatum.where(["key LIKE ?", "%#{type.last}%"]).first, :id, :parsed_key, options ={:prompt => "- #{type.first}"}) ))%>
    <% end %>
<% end %>

When I try to render the page in my browser, I get this error message:

undefined method `map' for #<Metadatum:0x1c9c68b38>

Here’s the offending code:

Metadatum.where(["key LIKE ?", "%#{type.last}%"]).first, :id, :parsed_key, options ={:prompt => "- #{type.first}"

Originally, I had Metadatum.all instead and the page rendered, but that isn’t the desired result.

Is there a simple way to filter options for a select box?

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  1. Editorial Team
    Editorial Team
    2026-05-22T03:18:37+00:00Added an answer on May 22, 2026 at 3:18 am

    A mindless programming mistake.

    I was calling .first on the collection. I removed it, and now it works.

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