Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 120093
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 11, 20262026-05-11T03:45:24+00:00 2026-05-11T03:45:24+00:00

I have a model Foo which have a ForeignKey to the User model. Later,

  • 0

I have a model Foo which have a ForeignKey to the User model.

Later, I need to grab all the User’s id and put then on a list

foos = Foo.objects.filter(...)  l = [ f.user.id for f in foos ] 

But when I do that, django grabs the whole User instance from the DB instead of giving me just the numeric user’s id, which exist in each Foo row.

How can I get all the ids without querying each user or using a select_related?

Thanks

  • 1 1 Answer
  • 2 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. 2026-05-11T03:45:24+00:00Added an answer on May 11, 2026 at 3:45 am

    Use queryset’s values() function, which will return a list of dictionaries containing name/value pairs for each attribute passed as parameters:

    >>> Foo.objects.all().values('user__id') [{'user__id': 1}, {'user__id' 2}, {'user__id': 3}] 

    The ORM will then be able to optimize the SQL query to only return the required fields, instead of doing a ‘SELECT *’.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have model Foo which has field bar. The bar field should be unique,
I have a model Foo which :has_many bars , initially I create and save
I have a User model which has_many Documents. Each Document's title must be unique
Simple Rails question. I have a model Foo which looks like this: class Foo
I have a model called Foo which has a property called MyProp of type
I have a model Foo and a model Bar, both of which has_many :bar_foos
I have an issue where I have a parent model Foo , which both
I have a model called Nonsense which has_one of Foo and Bar In my
I have an ActiveRecord model, Foo , which has a name field. I'd like
In GAE, I have a model called Foo, with existing entities, and attempt to

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.