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Home/ Questions/Q 3602076
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T20:42:03+00:00 2026-05-18T20:42:03+00:00

I have a model that checks for entries en a database. Like this: public

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I have a model that checks for entries en a database. Like this:

public function getByID($id)
{
    if(false == is_numeric($id))
        return false;

    $images = array();

    $query = $this->db->where("id_album", $id)->order_by("order", "ASC")->get("images");

    foreach($query->result() as $row)
        $images[] = $row;

    return (object) $images;
}

In my view I want to know if I have a rows or not, to show the images or not. I do this:

<?php if(false != isset($content->images)): ?>
    <pre><?php print_r($content->images); ?></pre>
<?php endif; ?>

But every time I try to skip when I’ve no results (i get a stdClass() empty) I fail. I tried isset, $content->images != NULL, !$content->images… I don’t know how to do it to skip the “Severity: Notice Message: Undefined variable”.

Thank you in advance.

UPDATE:

$content has more sets than images, like $content->_data or $content->title.

When I’ve NO images on database and i’ve no return from MySQL, doing this:

<?php echo count($content->images); ?>
<pre><?php print_r($content->images); ?></pre>

The output is:

1
stdClass ( )
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T20:42:04+00:00Added an answer on May 18, 2026 at 8:42 pm

    Why can’t you just use

    if(isset($content->images)) //Isset also will make sure $content is set
    {
        
    }
    

    This way your performing checks on both entities.

    As images is an object that can be iterated you can also check that.

    if(isset($content->images) && is_object($content->images))
    {
        
    }
    

    Also you seem to be using the wrong comparison operators for boolean’s, you should be using the strict standards for comparison, which is ===, and not ==, or !==, and not !=🙂

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