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Home/ Questions/Q 7497815
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T19:14:02+00:00 2026-05-29T19:14:02+00:00

I have a model that looks like this: from django.db import models from django.contrib.auth.models

  • 0

I have a model that looks like this:

from django.db import models
from django.contrib.auth.models import User

    class Application(models.Model):

        STATUS_CHOICES = (
        (u'IP',u'In Progress'),
        (u'C',u'Completed'))

        status = models.CharField(max_length=2 ,choices=STATUS_CHOICES, default='IP')
        title = models.CharField(max_length = 512)
        description = models.CharField(max_length = 5120)
        principle_investigator = models.ForeignKey(User, related_name='pi')

And I want to use a generic ListView that lists the applications for the currently logged in user, that have the status of ‘IP’

I started writting my urlpattern and realised that I would need to reference the currently logged in user in my queryset property….is this possible or will I need to bite the bullet and write a standard custom view that handles the model query?

Here is how far I got for illustration:

url(r'^application/pending/$', ListView.as_view(
      queryset=Application.objects.filter(status='IP'))),
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  1. Editorial Team
    Editorial Team
    2026-05-29T19:14:02+00:00Added an answer on May 29, 2026 at 7:14 pm

    You can’t filter on the user in your urls.py, because you don’t know the user when the urls are loaded.

    Instead, subclass ListView and override the get_queryset method to filter on the logged in user.

    class PendingApplicationView(ListView):
        def get_queryset(self):
            return Application.objects.filter(status='IP', principle_investigator=self.request.user)
    
    # url pattern
    url(r'^application/pending/$', PendingApplicationView.as_view()),
    
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