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Home/ Questions/Q 6938955
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T12:33:28+00:00 2026-05-27T12:33:28+00:00

I have a multi level select chain, where by the value of the first

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I have a multi level select chain, where by the value of the first select generates the options for the next select list. And within the second list some of the values will cause a div to display with another input.

My codes (below) seem to work just fine when tested on static content (ie: the second select is hard coded in the html). But when I add it with JQuery, the second level no longer triggers the .change function.

<script type="text/javascript">
$(document).ready(function() {
  $dts = $("select[name='tourdes']");
  $dts.change(function() { 
     var dtsValue = $(this).val();
     var dtsString = '?tourdes=' + dtsValue; 
     $('#dateSelect').show();
     $('#dateSelect').load('include/avdates.php' + dtsString).append();
  });
});
</script>

<script type="text/javascript">
$(document).ready(function() {
  $tags = $("select[name='tourcode']");
  $tags.change(function() {
     if ($(this).val() == "private") {
     $(".prvcal").css({"visibility":"visible"});
  }
  });
});
</script>

I am guessing something needs to be re-initialized, but I am getting no where with my experiments.

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  1. Editorial Team
    Editorial Team
    2026-05-27T12:33:28+00:00Added an answer on May 27, 2026 at 12:33 pm

    If you’re using jQuery 1.7 you’ll want to use on, as both live and delegate are deprecated.

    $(document).on("change", "select[name='tourcode']", function() {
        var dtsValue = $(this).val();
        var dtsString = '?tourdes=' + dtsValue; 
        $('#dateSelect').show();
        $('#dateSelect').load('include/avdates.php' + dtsString).append();
    });
    

    docs for on()

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