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Home/ Questions/Q 8098673
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T22:08:54+00:00 2026-06-05T22:08:54+00:00

I have a multithreaded application, in which I’m trying to render with different threads.

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I have a multithreaded application, in which I’m trying to render with different threads. First I tried to use the same Rendering Context between all threads, but I was getting NULL current contexts for other threads. I’ve read on the internet that one context can only be current at one thread at a time.

So I decided to make something different. I create a window, I get the HDC from it and create the first RC. AFter that, I share this HDC between threads, and in every new thread I create I obtain a new RC from the same HDC and I make it current for that thread. Everytime I do it, the RC returned is always different (usually the previous value + 1). I make an assertion to check if wglGetCurrentContext() returns a RC, and it looks like it returns the one that was just created. But after making the rendering, i get no rendering and if I call GetLastError() I obtain error 6 (invalid handle??)

So, does this mean that, despite every new call of wglCreateContext() gives me a new value, somehow it means that all these different values are the same “Connection channel” to the OpenGL calls?

Does this mean that I will always have to invalid the previous Rendering Context on a thread, and activate it on the new one? I really have to make this sync all the time or is there any other way to work arround this problem?

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  1. Editorial Team
    Editorial Team
    2026-06-05T22:08:56+00:00Added an answer on June 5, 2026 at 10:08 pm

    I have a multithreaded application, in which I’m trying to render with different threads.

    DON’T!!!

    You will gain nothing from trying to multithread your renderer. Basically you’re running into one large race condition and the driver will just be busy synchronizing the threads to somehow make sense of it.

    To gain best rendering performance keep all OpenGL operations to only one thread. All parallelization happens for free on the GPU.

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