Question

I have a MYSQL database that contains data on my companies customers as they use our services each day.

each table in the database represents one 24 hour period and all customer transactions that took place in that period.

I would like to count the total transactions over a number of days

so far I have a select statement that does the following

select 
  (
    select count(customer) from 2010Dec28 
    where customer='<customer name>'
  ) as t1,
  (
    select count(customer) from 2010Dec29 
    where customer='<customer name>'
  )as t2;`

but this returns the result as two separate counts

| t1   | t2    |
| 1438 | 16282 |
1 row n set (0.00 sec)`

My question is how can I generate the sum of these two results without having to do so in my application code.

Answer 1

Tyler is probably right, design is surely wrong!

But it is possible..

select 
    sum(a.count)
from
    (select count(*) as count from table1
     union all
     select count(*) as count from table2) a