Question

I have a mysql db with two tables. The first table is called ‘uniqueReferences’ and the second one ‘duplicatedReferences’. The two tables have two fields only: an id field (auto-incremented) and a field called Reference. What I would like is as follows. When trying to insert a ref in the ‘uniqueReferences’ table, if the reference already exists, do not insert it in that table but in the table ‘duplicatedReferences’.

So what I tried but did not work is the following.
1-> set the field reference of my ‘uniqueReferences’ table as ‘unique’.
2-> Make the following

try{  
         $req = $prepared_insertQry_toUniqueRefTable -> execute(array(something));

         if($req == 0){
               $prepared_insertQry_toDuplicateRefTable->execute(array(something));
         }
     }
    catch(PDOException $e){echo $e->getMessage();}

This is unfortunately not working. I have the following error SQLSTATE[23000]: Integrity constraint violation: 1062 Duplicate entry. Hope someone can help. Cheers. Marc

Answer 1

See my notes inline with the code:

    try{  
         $req = $prepared_insertQry_toUniqueRefTable -> execute(array(something));

         // this never executes because an Exception halts it here
         /*if($req == 0){
               $prepared_insertQry_toDuplicateRefTable->execute(array(something));
         }*/
     }
    catch(PDOException $e){
       // this catch grabs the exception and executes the code within instead
       // that code might log an error, echo the error message, or perform
       // alternative logic. In your case you want to execute alterntative logic
       // ie. your query
       $prepared_insertQry_toDuplicateRefTable->execute(array(something));

   }