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Home/ Questions/Q 950599
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T23:35:34+00:00 2026-05-15T23:35:34+00:00

I have a MySQL singleton class written in PHP. Its code is listed below:

  • 0

I have a MySQL singleton class written in PHP. Its code is listed below:

class Database {
    private $_result = NULL;
    private $_link = NULL;
    private $_config = array();
    private static $_instance = NULL; 

    // Return singleton instance of MySQL class
    public static function getInstance(array $config = array()) {
        if (self::$_instance === NULL) {
            self::$_instance = new self($config);
        }

        return self::$_instance;
    }

    // Private constructor
    private function __construct(array $config) {
        if (count($config) < 4) {
            throw new Exception('Invalid number of connection parameters');  
        }

        $this->_config = $config;
    } 

    // Prevent cloning class instance
    private function __clone() {}

    // Connect to MySQL
    private function connect() {
        // Connect only once
        static $connected = FALSE;

        if ($connected === FALSE) {
            list($host, $user, $password, $database) = $this->_config;

            if ((!$this->_link = mysqli_connect($host, $user, $password, $database))) {
                throw new Exception('Error connecting to MySQL : ' . mysqli_connect_error());
            }

            $connected = TRUE;

            unset($host, $user, $password, $database);      
        }
    } 

    // Perform query
    public function query($query) {
        if (is_string($query) and !empty($query)) {
            $this->connect();
            if ((!$this->_result = mysqli_query($this->_link, $query))) {
                throw new Exception('Error performing query ' . $query . ' Message : ' . mysqli_error($this->_link));
            }
        }
    }

    // Fetch row from result set
    public function fetch() {
        if ((!$row = mysqli_fetch_object($this->_result))) {
            mysqli_free_result($this->_result);
            return FALSE;
        }

        return $row;
    }

    // Get insertion ID
    public function getInsertID() {
        if ($this->_link !== NUlL) {
            return mysqli_insert_id($this->_link); 
        }

        return NULL;  
    }

    // Count rows in result set
    public function countRows() {
        if ($this->_result !== NULL) {
           return mysqli_num_rows($this->_result);
        }

        return 0;
    }  

    // Close the database connection
    function __destruct() {
        is_resource($this->_link) AND mysqli_close($this->_link);
    }    
}

I also have this recursive function which must returns a full category tree (the SQL table and its content can be found here):

function getCategories($parent = 0) {
    $html = '<ul>';    
    $query = "SELECT * FROM `categories` WHERE `category_parent` = '$parent'";
    $database->query($query);    
    while($row = $database->fetch()) {
        $current_id = $row->category_id;
        $html .= '<li>' . $row->category_name;
        $has_sub = 0;
        $query = "SELECT `category_parent` FROM `categories` WHERE `category_parent` = '$current_id'";
        $database->query($query);
        $has_sub = $database->countRows();

        if ($has_sub > 0) {        
            $html .= getCategories($current_id);
        }

        $html .= '</li>';
    }

    $html .= '</ul>';
    return $html;
}

Now, the problem is that the function returns only 3 categories, not the full tree. I rewrote the function using plain MySQL functions (mysql_query(), mysql_fetch_object() etc.) and it returns the right result.

So my conclusion in that there’s something wrong with that class. Note that I’ve been using this class in most of my projects, but never had this issue.

Any idea what?

Thanks.

EDIT: Trying to make it to return an associative array

function getCategories($parent = 0) {
    global $database;
    $categories = array();

    $query = "SELECT * FROM `categories` WHERE `category_parent` = '$parent'";
    $database->query($query);    
    while($row = $database->fetch()) {
        $categories[] = array('id' => $row->category_id, 'name' => $row->category_name);        
    }

    for ($i = 0; $i < count($categories); $i++) {

        $categories[$i]['id']['children'] = getCategories($categories[$i]['id']);

    }

    return $categories;
}

The code above returns the following array, but is not quite ok:

Array
(
    [0] => Array
        (
            [id] => 1
            [name] => Categoria 1
            [children] => Array
                (
                    [0] => Array
                        (
                            [id] => 4
                            [name] => Categoria 1.1
                            [children] => Array
                                (
                                    [0] => Array
                                        (
                                            [id] => 7
                                            [name] => Categoria 1.1.2
                                            [children] => Array
                                                (
                                                )

                                        )

                                )

                        )

                    [1] => Array
                        (
                            [id] => 5
                            [name] => Categoria 1.2
                            [children] => Array
                                (
                                )

                        )

                    [2] => Array
                        (
                            [id] => 6
                            [name] => Categoria 1.3
                            [children] => Array
                                (
                                )

                        )

                )

        )

    [1] => Array
        (
            [id] => 2
            [name] => Categoria 2
            [children] => Array
                (
                )

        )

    [2] => Array
        (
            [id] => 3
            [name] => Categoria 3
            [children] => Array
                (
                )

        )
)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T23:35:35+00:00Added an answer on May 15, 2026 at 11:35 pm

    The problem that you’re seeing is that you a running other queries over your first query. So after you recurse through the first branch the function fails because it goes back to the original which loop and finds that its already at the end of the resulting rows from the first branch (3 levels of recursion in).

    A quick fix would be to rewrite your function using two loops instead of just one. You can also optimise the function this way too by reducing the number of DB calls you have to make.

    Your first query is fine. But in your while loop, just grab the appropriate id and name elements and store them in an array. Then reloop through the array that you just created to recurse. Also, you can eliminate several queries by not running a “check” query. Just recurse – and if there are no elements the id:name array – return an empty string.

    EDIT: an example (untested)

    function getCategories($parent = 0) {
        $categories = array();
        $html = "<ul>";
        $query = "SELECT * FROM `categories` WHERE `category_parent` = '$parent'";
        $database->query($query);    
        while($row = $database->fetch()) {
            $categories[$row->category_id] = $row->category_name;
        }
        foreach($categories as $cid=>$category) {
            $html .= "<li>{$row->category_name}";
            $inner = getCategories($cid);
            if($inner != "<ul></ul>")
                $html .= $inner;
            $html .= "</li>"
        }
        $html .= "</ul>";
        return $html;
    }
    
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