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Home/ Questions/Q 6776277
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T16:00:31+00:00 2026-05-26T16:00:31+00:00

I have a mysql table like this (sql): CREATE TABLE IF NOT EXISTS silver_and_pgm

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I have a mysql table like this (sql):

CREATE TABLE IF NOT EXISTS silver_and_pgm (
_metal_name varchar(30) NOT NULL,
_bid varchar(30) NOT NULL,
_change varchar(30) NOT NULL
) ENGINE=MyISAM DEFAULT CHARSET=latin1;

—

— Dumping data for table silver_and_pgm

INSERT INTO silver_and_pgm (_metal_name, _bid, _change) VALUES
(‘Silver\r\n’, ‘555’, ‘-0.22\r\n’),
(‘Platinum\r\n’, ‘555’, ‘-9.00\r\n’),
(‘Palladium\r\n’, ‘555’, ‘0.00\r\n’),
(‘Rhodium\r\n’, ‘555’, ‘0.00\r\n’);

and i am using the following code to update a row which contains metal_name as Silver

<?php

$username = "root";
$password = "1234";
$database = "kitco";
$con=mysql_connect(localhost,$username,$password);
mysql_select_db($database) or die( "Unable to select database");

$bid = '101010';
$metal_name = 'Silver';

$query = "update silver_and_pgm set _bid='$bid' where _metal_name='$metal_name'";
//$query2 = "update silver_and_pgm set _bid='444'";;
echo $query."<br>";
$result = mysql_query($query);
if(!$result)echo "error";

?>

but $query doesn’t work . it works fine if I use $query2 . If I use the same query directly in SQL of phpmyadmin result is same.
what is the problem with $query . I think its correct.
Would anybody please find the bug ??

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T16:00:31+00:00Added an answer on May 26, 2026 at 4:00 pm

    It looks like you have a line break in your _metal_name in the database, the SQL query says Silver\r\n.

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