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Home/ Questions/Q 8715525
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T05:52:01+00:00 2026-06-13T05:52:01+00:00

I have a MYSQL table which stores teams. Table structure: CREATE TABLE teams (

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I have a MYSQL table which stores teams.

Table structure:
CREATE TABLE teams (
id int(11) NOT NULL AUTO_INCREMENT,
name varchar(28) COLLATE utf8_unicode_ci NOT NULL,
UNIQUE KEY id (id)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=1;

Sample data:
INSERT INTOteamsVALUES
(1, 'one'),
(2, 'two'),
(3, 'three'),
(4, 'four'),
(5, 'five');

Use:
SELECT id, name, id as rowNumber FROM teams WHERE id = 4
Returns the correct rowNumber, as there are really three rows infront f it in the table. But this only works as long as I don’t remove a row.

Example:
Let’s say I DELETE FROM teams WHERE id = 3;
When I now use SELECT id, name, id as rowNumber FROM teams WHERE id = 4 the result is wrong as there are now only two rows (id’s 1&2) infront of it in the table.

How can I get the “real” row number/index ordered by id from one specific row?

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  1. Editorial Team
    Editorial Team
    2026-06-13T05:52:02+00:00Added an answer on June 13, 2026 at 5:52 am

    You are rturning ID as rowNumber, so it simply returning ID column value. Why do you expect it to be different?

    I think you may want to define and @curRow variable to get the row number as and use sub query as below:

     SELECT * from 
        (SELECT  ID, 
             NAME, 
             @curRow := @curRow + 1 AS rowNumber
          FROM    Teams t
          JOIN    (SELECT @curRow := 0) curr
          ORDER by t.ID asc) as ordered_team
     WHERE ordered_team.id = 4;
    
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