Question

I have a MySQL table with a number of columns, including one called ‘Name’.

I would like to design a form for a webpage which consists of two textboxes, A and B. In textbox A the user would be required to enter their name, and in textbox B some other information.

I would like the PHP script to check if the Name in Textbox A matches a value already in the Name column in the MySQL table, and if it does, add the value in Textbox B to another column in this table. If the name is not found, I would like the script to return an error, along the lines of “Your booking was not found on our database”.

Is it possible to do this using PHP/MySQL and if it is, how would I go about this?

CURRENT CODE

$row_count = count($_POST['name']);

mysql_select_db($database, $connection);

if ($row_count > 0) {

$values = array();

 for($i = 0; $i < $row_count; $i++) {
     // variable sanitation...
     $name = mysql_real_escape_string(ucwords($_POST['name'][$i]));
     $workshop = mysql_real_escape_string($_POST['workshop'][$i]);

     $query = "SELECT * FROM conference WHERE Name = '$name' ";
     $result = mysql_query($query);

     if ($result) {
     $rowcount = mysql_num_rows($result);

     if ($rowcount == 0) {echo "no bookings found"; }
     else {
     $row = mysql_fetch_row($result);
     $sql = "UPDATE conference SET Workshop = '$workshop' WHERE Name = '$name'";
     mysql_query($sql);
     }

     }
}

}

Answer 1

This should get you started.

//Get the value from the textbox
$name = mysql_real_escape_string($_POST['name']);
//Select all rows with the name
$query = "SELECT other_info FROM table1 WHERE name = '$name' ";
$result = mysql_query($query);
if ($result) {
  $rowcount = mysql_num_rows($result);
  //No rows found
  if ($rowcount == 0) {echo "no bookings found"; }
  else {
    //process the data.
    $row = mysql_fetch_row($result);
    $other_info = $row['other_info'];
    echo "other_info = ".hmtlentities($other_info);

See here: http://php.net/manual/en/book.mysql.php

Comments on the code

$row_count = count($_POST['name']);
if ($row_count > 0) {

  mysql_select_db($database, $connection);
  //$values = array(); 
  $name = array();
  $workshop = array()
  $replace = array()

  for($i = 0; $i < $row_count; $i++) {
    // variable sanitation...
    $name[i] = mysql_real_escape_string(ucwords($_POST['name'][$i]));
    $workshop[i] = mysql_real_escape_string($_POST['workshop'][$i]);
    //if you use option 2
    $replace[i] = "('".$name[i]."','".$workshop[i]."')";
  }
  $names = "'".implode("','",$name)."'";
  $query = "SELECT 1 FROM conference WHERE Name IN $names "; 
  $result = mysql_query($query);

  if ($result) {
    $rowcount = mysql_num_rows($result);

    if ($rowcount == 0) {
      echo "<HTMLCODE HERE>"."no bookings found"."<MORE HTML>"; 
    //OPTION 1
    } else {
      for($i = 0; $i < $row_count; $i++) {
        //$row = mysql_fetch_row($result);  
        $sql = "UPDATE conference SET Workshop = '$workshop[i]' 
                WHERE Name LIKE '$name[i]'";
        mysql_query($sql);
      }
    }
    //OPTION2
    } else {
      $replacement = implode(",",$replace);
      $sql = "REPLACE INTO conference (names, workshop) VALUES $replacement "
      mysql_query($sql);
    }
  }
}