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Asked: 2026-05-24T22:38:07+00:00

I have a number stored as a string up to 16 chars (0 to

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I have a number stored as a string up to 16 chars (0 to F) in length. This needs to be incremented and the result stored as a string.

Simplest thing would have been to convert the string to an int, increment by one, then convert back to a string. However the OS doesn’t support 64 numbers. What’s the alternative?

I presume a hand crafted solution using two 32 bit integers is possible, in which case this must be a common scenario, but I couldn’t find any boilerplate template code for doing such a thing after a bit of googling.

UPDATE: Sorry – sould have mentioned earlier – This is for Brew MP C++ – their conversion libraries’ APIs are limited to 32 bit.

And experimenting with long long seems to have fundamental big time problems in general executing on hardware, making it unusable.

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1 Answer

  1. Editorial Team

    You can increment one digit at a time. If the digit is between ‘0’ and ‘8’, just add one; likewise if it’s between ‘A’ and ‘E’. If it’s ‘9’, set it to ‘A’. If it’s ‘F’, set it to ‘0’ and increment the next digit to the left.

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