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Home/ Questions/Q 8580519
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T20:50:54+00:00 2026-06-11T20:50:54+00:00

I have a object which I want to serialize to JSON. This object is

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I have a object which I want to serialize to JSON. This object is a map with list of a specific objects. This looks similar to it:

Map<String, List<Object>> map = new Map<String, List<Object>>();

I am using FlexJSON. I can work only with flexjson.JSONSerializer. There are my tries:

JSONSerializer jsonSerializer = new JSONSerializer();
//        jsonSerializer.include("map");
//        jsonSerializer.include("map.myList.object");
jsonSerializer.transform(new MapTransformer(), "map");
jsonSerializer.exclude("*.class");

As you can see I am trying now with Transformer classes but I haven’t succeeded. The commented lines will work, as I suppose, if my List<Object> has own name for example myList. But it doesn’t haven own name, because it is values of my map.

How can I serialize such object to JSON with FlexJSON?

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  1. Editorial Team
    Editorial Team
    2026-06-11T20:50:55+00:00Added an answer on June 11, 2026 at 8:50 pm

    Quoi is correct, and most likely the answer you want to use. However, just so you can learn more about how it works you could do this:

    new JSONSerializer().include("values.values").serialize( myMap );
    

    Maps and Lists are containers and have special expressions for the elements contained within them. When you want to talk about the path of the values of a container you use “values” expression in the path. Map’s two special expressions “keys” and “values”. Other Collections have “values”.

    Another option is to use wildcards like so:

       new JSONSerializer().include("values.*").serialize( myMap );
    

    You can see wildcards used in Quoi’s answer as well to exclude the class property.

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