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Home/ Questions/Q 6696537
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T06:21:11+00:00 2026-05-26T06:21:11+00:00

I have a page that has 50 elements with the same class fields which

  • 0

I have a page that has 50 elements with the same class “fields” which are all display none at the moment

<div class="fields" style="display:none;">
    ...
</div>
<div class="fields" style="display:none;">
    ...
</div>
<div class="fields" style="display:none;">
    ...
</div>
<div class="fields" style="display:none;">
    ...
</div>
...

How to I only show the first 3 or whatever number. Plus count them with a count on top like the following example below.

So for example if I needed the first 3 this is what i need the divs to look like

<div class="fields">
    <h1>Station 1</h1>
</div>
<div class="fields">
    <h1>Station 2</h1>

</div>
<div class="fields">
    <h1>Station 3</h1>
</div>
<div class="fields" style="display:none;">
    ...
</div>
...

So basically only some the number of divs that I need…I already have the number of elements I need to show in this blur statement in the station_count variable. Also notice i need a span tag with the count..any ideas on how to do this

    $("#number_station").blur(function(){
        var station_count = $(this).val();
                    //code goes there
    });
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T06:21:12+00:00Added an answer on May 26, 2026 at 6:21 am

    How to I only show the first 3 or whatever number.

    $('div.fields:lt(3)').show();
    

    Plus count them with a count on top

    $('div.fields:lt(3)').each(function (index)
    {
        $('<h1></h1>', {text: 'Station ' + index}).prependTo(this);
    }).show();
    

    Demo: http://jsfiddle.net/mattball/TssUB/


    Read the jQuery API docs for basic questions like this:

    • :lt() selector
    • .prependTo()
    • jQuery() (for creating new elements)
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