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Home/ Questions/Q 9151173
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T11:44:16+00:00 2026-06-17T11:44:16+00:00

I have a page where a user can ‘like’ an article. When the page

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I have a page where a user can ‘like’ an article.

When the page first loads I want to show if they’ve already liked an article.

The code I’m using to add html to the DOM is:

html += '<div class="gl_like">';
html += '<a href="#" class="like" id="'+image.article_id+'"><div class="bLike" title="Like this article"></div></a>';
html += '<a href="#" class="unlike" id="'+image.article_id+'"><div class="bUnlike" title="Unlike this article"></div></a>';
html += '</div>';

Now I’m checking what the API throws back as to whether a user has already liked an article

if(image.numLikes<1){
$('.like').show();
$('.unlike').hide();
html += 'wooo'; // to test the code works, it does
} else {
$('.like').hide();
$('.unlike').show();
}

The “wooo” is added to the html but the show/hide functions are being ignored. The “.like” class is shown on every article.

What I want to happen is the “.like” class shows if user hasn’t liked an article and “.unlike” class shows if they have.

Am I missing something here?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T11:44:18+00:00Added an answer on June 17, 2026 at 11:44 am

    Got it guys, thanks:

    if(image.numLikes<1){
        html += '<a href="#" class="like" id="'+image.article_id+'"><div class="bLike" title="Like this article"></div></a>';
        html += '<a href="#" class="unlike" id="'+image.article_id+'" style="display:none;"><div class="bUnlike" title="Unlike this article"></div></a>';
        } else {
        html += '<a href="#" class="like" id="'+image.article_id+'" style="display:none;"><div class="bLike" title="Like this article"></div></a>';
        html += '<a href="#" class="unlike" id="'+image.article_id+'"><div class="bUnlike" title="Unlike this article"></div></a>';
        }
    

    Instead of using show/hide its easier to literally show or hide.

    Not sure I explained the question very well either, apologies for that but thanks a bunch for the answers.

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