Question

I have a page with Four Item buttons, when the user click on these buttons the Content should slideDown.

If it is already a visible content this content must be slided up and then the right content should be slided Down.

Everything works fine, but if the user click fast between the Item Buttons the slides get jammed and start to appear on top of the others.

Here is an example.:
http://jsfiddle.net/7t6Eh/42/

If the user click “slow” between the Items, everything works ok.

• To re-create the error Click Fast Between the Item Buttons.

I’ve already tried to use ‘.is(“: visible”)’ but got the same results.

Can anyone help me out?

CODE

var active = 0;

    $("#item1").click(function(){

        if (active == 0){

            $("#ContentList1").stop().slideToggle(function() {
                active = 1;
            });

        } else {

            if (active != 1){
                $("#ContentList" + active).stop().slideToggle(function() {

                    $("#ContentList1").stop().slideToggle(function() {
                        active = 1;
                    });

                });
            }
        }
    });

    $("#item2").click(function(){

        if (active == 0){

            $("#ContentList2").stop().slideToggle(function() {
                active = 2;
            });

        } else {

            if (active != 2){
                $("#ContentList" + active).stop().slideToggle(function() {

                    $("#ContentList2").stop().slideToggle(function() {
                        active = 2;
                    });

                });
            }
        }
    });

    $("#item3").click(function(){

        if (active == 0){

            $("#ContentList3").stop().slideToggle(function() {
                active = 3;
            });

        } else {

            if (active != 3){
                $("#ContentList" + active).stop().slideToggle(function() {

                    $("#ContentList3").stop().slideToggle(function() {
                        active = 3;
                    });

                });
            }
        }
    });    

    $("#item4").click(function(){

        if (active == 0){

            $("#ContentList4").stop().slideToggle(function() {
                active = 4;
            });

        } else {

            if (active != 4){
                $("#ContentList" + active).stop().slideToggle(function() {

                    $("#ContentList4").stop().slideToggle(function() {
                        active = 4;
                    });

                });
            }
        }
    });

Answer 1

I usuallly do this kind of things taking advantage of siblings() to select adjacent divs and stop them, rather than using an “active” var to store the active div:

$(document).ready(function(){
    $("#item1").click(function(){
        $('#' + $(this).attr('for'))
            .slideDown().siblings('div').stop().slideUp()
    });
    $("#item2").click(function(){
        $('#' + $(this).attr('for'))
            .slideDown().siblings('div').stop().slideUp()
    });
    $("#item3").click(function(){
        $('#' + $(this).attr('for'))
            .slideDown().siblings('div').stop().slideUp()
    });
    $("#item4").click(function(){
        $('#' + $(this).attr('for'))
            .slideDown().siblings('div').stop().slideUp()
    });
});

you can use the “for” attribute (or any other) to specify the div that the link is referring. For example:

<div id="item1" for="ContentList1" style="float: left; width: 50px; cursor: pointer;">Item1</div>

​
An example working fiddle: http://jsfiddle.net/7t6Eh/46/

ADDED: If you want to do the close animation before the open animation, you can use jQuery deferred like this:

$("#item1").click(function(){
    content = $('#' + $(this).attr('for'));
    $.when(content.siblings('div').stop().slideUp())
        .then(function () { content.slideDown() });
});

of course apply to all 4 click events. Example: http://jsfiddle.net/7t6Eh/52/