Question

I have a page with two different View Models:

<?page title="My page" contentType="text/html;charset=UTF-8"?>
<div apply="org.zkoss.bind.BindComposer"
viewModel="@id('vm') @init('com.mycompany.FirstViewModel')">
<!-- A lot of unimportant stuff -->
<tabbox>
    <tabs>
        <tab label="Tab1" ></tab>
                    <!-- Other unimportant tabs -->
    </tabs>
    <tabpanels>
        <tabpanel>
        <include src="inc/other.zul" p="@ref(vm.selected)" pid="@ref(vm.selected.id)" ></include>
        </tabpanel>
    </tabpanels>
</tabbox>
</div>

And the include is:

<window>
    <label id="sid" value="@load(pid)" />
    <div apply="org.zkoss.bind.BindComposer"
      viewModel="@id('vms') @init('com.mycompany.SecondViewModel')">
        <listbox model="@id('vars') @load(p.someList)"
            selectedItem="@bind(vms.selected)"
            emptyMessage="No data in list">
                    <!-- Template and stuff -->
        </listbox>
        <label id="sid1" value="@load(pid)" />
    </div>
</window>

The problem is that once I define the second viewModel, all the external references are inaccessible: I have a value for the first label, but I have no values for the listbox or the second label. Is there a way to do that? I tried with no success to do this:

<div apply="org.zkoss.bind.BindComposer"
viewModel="@id('vms') @init('com.mycompany.SecondViewModel')" list="@ref(p.someList)">
<listbox model="@id('vars') @load(list)"
    selectedItem="@bind(vms.selected)"
    emptyMessage="No data in list">

I could merge the second View Model in the first one, but that wouldn’t be very convenient! I am also open to other solutions which allow me to have a modular approach.

My version of ZK is 6.0.1

Answer 1

It is (was) actually a bug in ZK, which has been fixed for a future version.