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Home/ Questions/Q 8569153
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T18:16:08+00:00 2026-06-11T18:16:08+00:00

I have a pattern which I use with wildcard in order to find files.

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I have a pattern which I use with wildcard in order to find files. The pattern is specified in a variable as it is intended to be configurable (it’s in an included makefile). I then need to use the same pattern with patsubst. Is there an easy way switch the * for a %? Obviously there could only be one * in the wildcard pattern.

So, for example, if my wildcard pattern is *.c then I would like to obtain the pattern %.c

This would also need to work for the the following wildcard patterns:

WILD := *.c *.s *.S
WILD := prefix_*.suffix

I had a solution for the first case, where I am just working with extensions, which is to use patsubst itself:

PATSUBST_PATTERN := $(patsubst *.%,\%.%,$(WILD))

Can anyone suggest a way to do this where the * is not at the start of the wildcard pattern?

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  1. Editorial Team
    Editorial Team
    2026-06-11T18:16:09+00:00Added an answer on June 11, 2026 at 6:16 pm

    What about

    WILD := *.c *.s *.S prefix_*.suffix
    PATSUBST_PATTERN := $(subst *,%,$(WILD))
    $(info $(PATSUBST_PATTERN))
    

    Output:

    %.c %.s %.S prefix_%.suffix
    
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