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Home/ Questions/Q 300301
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T06:54:05+00:00 2026-05-12T06:54:05+00:00

I have a pattern with a small list of words that are illegal to

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I have a pattern with a small list of words that are illegal to use as nicknames set in a pattern variable like this:

$pattern = webmaster|admin|webadmin|sysadmin

Using preg_match, how can I achieve so that nicknames with these words are forbidden, but registering something like “admin2” or “thesysadmin” is allowed?

This is the expression I have so far:

preg_match('/^['.$pattern.']/i','admin');

// Should not be allowed

Note: Using a \b didn’t help much.

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  1. Editorial Team
    Editorial Team
    2026-05-12T06:54:06+00:00Added an answer on May 12, 2026 at 6:54 am

    What about not using regex at all ?

    And working with explode and in_array ?

    For instance, this would do :

    $pattern = 'webmaster|admin|webadmin|sysadmin';
    $forbidden_words = explode('|', $pattern);
    

    It explodes your pattern into an array, using | as separator.

    And this :

    $word = 'admin';
    if (in_array($word, $forbidden_words)) {
        echo "<p>$word is not OK</p>";
    } else {
        echo "<p>$word is OK</p>";
    }
    

    will get you

    admin is not OK
    

    Whereas this (same code ; only the word changes) :

    $word = 'admin2';
    if (in_array($word, $forbidden_words)) {
        echo "<p>$word is not OK</p>";
    } else {
        echo "<p>$word is OK</p>";
    }
    

    will get you

    admin2 is OK
    

    This way, no need to worry about finding the right regex, to match full-words : it’ll just match exact words 😉


    Edit : one problem might be that the comparison will be case-sensitive 🙁

    Working with everything in lowercase will help with that :

    $pattern = strtolower('webmaster|admin|webadmin|sysadmin');  // just to be sure ;-)
    $forbidden_words = explode('|', $pattern);
    
    $word = 'aDMin';
    if (in_array(strtolower($word), $forbidden_words)) {
        echo "<p>$word is not OK</p>";
    } else {
        echo "<p>$word is OK</p>";
    }
    

    Will get you :

    aDMin is not OK
    

    (I saw the ‘i‘ flag in the regex only after posting my answer ; so, had to edit it)


    Edit 2 : and, if you really want to do it with a regex, you need to know that :

    • ^ marks the beginning of the string
    • and $ marks the end of the string

    So, something like this should do :

    $pattern = 'webmaster|admin|webadmin|sysadmin';
    
    $word = 'admin';
    if (preg_match('#^(' . $pattern . ')$#i', $word)) {
        echo "<p>$word is not OK</p>";
    } else {
        echo "<p>$word is OK</p>";
    }
    
    $word = 'admin2';
    if (preg_match('#^(' . $pattern . ')$#i', $word)) {
        echo "<p>$word is not OK</p>";
    } else {
        echo "<p>$word is OK</p>";
    }
    

    Parentheses are probably not necessary, but I like using them, to isolate what I wanted.

    And, you’ll get the same kind of output :

    admin is not OK
    
    admin2 is OK
    

    You probably don’t want to use [ and ] : they mean “any character that is between us”, and not “the whole string that is between us”.

    And, as the reference : manual of the preg syntax 😉

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