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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T20:37:26+00:00 2026-05-12T20:37:26+00:00

I have a performance bottleneck on a DataView.Sort. The code is below. /// <summary>

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I have a performance bottleneck on a DataView.Sort. The code is below.

    /// <summary>
    /// Filters the data table and returns a new data table with only the filtered rows.
    /// </summary>
    /// <param name="dtInput">The dt input.</param>
    /// <param name="filterExpression">The filter expression.</param>
    /// <returns></returns>
    protected virtual DataTable FilterDataTable(DataTable dtInput, string filterExpression)
    {
        DataTable result = dtInput;
        if (!string.IsNullOrEmpty(filterExpression) && filterExpression.Trim().Length > 0)
        {
            DataView view = new DataView(dtInput);
            view.RowFilter = filterExpression;
            view.Sort = HierarchyFieldMap.DisplayedValue;
            result = view.ToTable();
        }
        return result;
    }

Any idea’s on how to improve this method?

It takes ~1 second to execute.

EDIT

I found this link on DataView’s Poor Peformance with Large RecordSets

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  1. Editorial Team
    Editorial Team
    2026-05-12T20:37:27+00:00Added an answer on May 12, 2026 at 8:37 pm

    Since you’re not returning a DataView but a DataTable, you should be able to get a performance boost – not order-of-magnitude, but 25-30% – by using DataTable.Sort:

    private static DataTable SortDataTable(DataTable t, 
       string filterExpression,
       string sortExpression)
    {
        DataTable t1 = t.Clone();
        t1.BeginLoadData();
        foreach (DataRow r in t.Select(filterExpression, sortExpression))
        {
            t1.Rows.Add(r.ItemArray);
        }
        t1.EndLoadData();
    
        return t1;
    }
    

    Most of the time that’s being taken up there is copying the data into the new table. If you can avoid creating a new table and work with the array of DataRows that DataTable.Select returns you can get a considerable improvement.

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