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Asked: 2026-05-11T23:29:14+00:00

I have a Pervasive database that I connect to using C++. All my queries

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I have a Pervasive database that I connect to using C++.
All my queries so far is parameterized, i.e "SELECT USER.NAME FROM USER WHERE USER.ID = ?",
and that works fine.
But in a search query I use LIKE in the WHERE clause, and then it seems I can’t use parameters and wild chars (%).

My query looks something like this "SELECT * FROM DOG WHERE DOG.NAME LIKE '%?%'" and since there are two ‘ around the parameter ?-mark, this fails, it searched for dogs with a ?-mark in their name. In SQL Server this would probably be solved by concatenating the string like "SELECT * FROM DOG WHERE DOG.NAME LIKE '%' + ? + '%'", but this is invalid syntax in Pervasive (see bottom of this page: http://ww1.pervasive.com/library/docs/psql/950/sqlref/sqlref-04-55.html).

I’ve also tried to add the %-signs to the parameter itself, but that doesn’t seem to work either.

Does anyone know a solution to this?

EDIT1:
Some C++ Code example:

CString sqlCommand = "SELECT * FROM DOG WHERE DOG.NAME LIKE ?;";
m_pAdoCommand->CommandText = _bstr_t(sqlCommand);
m_pAdoCommand->Parameters->Append( m_pAdoCommand->CreateParameter("p0", adVarChar, adParamInput, 25, _bstr_t("'%bob%'")) );
m_pAdoRecordset = m_pAdoCommand->Execute(NULL,NULL,adCmdText);

(m_pAdoCommand is a _CommandPtr, and m_pAdoRecordset is a _RecordsetPtr. I’ve changed the name of the SQL Tables in this example so that they make sens here.)

The above code will return a row with a dog that has the name '%bob%', but I would like it to return all dogs that have bob in their name.

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1 Answer

  1. Editorial Team

    Why don’t you add a wildcard to the value you’re assigning to the parameter ?

    So, this means, your query looks like

    SELECT * FROM dog WHERE dog.name LIKE ?

    And then, you assign the value ‘%bob%’ to this parameter, for instance.
    I see you say that you’ve tried this as well, but it doesn’t work, which is very strange. Can you show the code of what you’ve done then ?

    I also see that you put quotes around the parameter in one of your examples. This doesn’t sound like a good idea, since then the parameter won’t be recognized as a parameter anymore. At that point, it is just a string.

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