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Home/ Questions/Q 8398149
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T20:58:11+00:00 2026-06-09T20:58:11+00:00

I have a PHP code that actively generates a Select input with 5 different

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I have a PHP code that actively generates a Select input with 5 different options in it.

Now, I also want to show the number 2, 3, 4 and 5 in a div as text as well.

Note that I want to ommit the first option in my DIV.

<select>
<option>1</option>
<option>2</option>
<option>3</option>
<option>4</option>
<option>5</option>
</select>

Also to be displayed accordingly:

<div><img src="#" /> 2</div>
<div><img src="#" /> 3</div>
<div><img src="#" /> 4</div>
<div><img src="#" /> 5</div>

I tried doing this with document.forms[0].select.value; but it only shows the selected value and not all the options. Furthermore, I want to filter the first option so what should I do? Any help is appreciated.


Actual HTML of the select element, provided by OP in comments to an answer:

<select class="last" id="property_types" name="property_types">
    <option selected="selected" value="0">View all Property Types</option>
    <option value="96" class="level-0">Apartment</option>
    <option value="9" class="level-0">Building</option>
    <option value="3" class="level-0">Land</option>
    <option value="97" class="level-0">Office</option>
</select>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T20:58:12+00:00Added an answer on June 9, 2026 at 8:58 pm

    I’d suggest:

    $('option').slice(1).each(
        function(){
            var text = $(this).text(),
                outputTo = $('#output'),
                div = $('<div />').text(text),
                img = $('<img />', {'src' : '#'}).prependTo(div);
            div.appendTo(outputTo);
        });​
    

    JS Fiddle demo.

    Note that this assumes a specific div is used in order to contain the output of this approach, obviously adjust to taste.

    Above code amended to provide a specific selector, in response to the OP’s posting code in the comments to this answer:

    $('#property_types option').slice(1).each(
        function(){
            var text = $(this).text(),
                outputTo = $('#output'),
                div = $('<div />').text(text),
                img = $('<img />', {'src' : '#'}).prependTo(div);
            div.appendTo(outputTo);
        });​
    

    References:

    • appendTo().
    • each().
    • prependTo().
    • slice().
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