Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6968601
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 27, 20262026-05-27T16:28:21+00:00 2026-05-27T16:28:21+00:00

I Have a PHP file doing a query function getFiles() { $solnid = $_GET[id];

  • 0

I Have a PHP file doing a query

function getFiles()
{
    $solnid = $_GET[id];
    $query = mysql_query("SELECT * FROM library WHERE libr_solutionId = '$solnid' AND libr_deleted IS NULL") or die(mysql_error());
    $result = mysql_query($query);
    if (mysql_num_rows($result)==0) {
        echo "<br>No Related Links";
    } else {
        while($library = mysql_fetch_assoc($query)) {
            echo "<span style=\"margin-bottom: 5px;\"><a href=\"Solutions/image/".$library[libr_solutionref]."/".$library[libr_filename]."\" target=\"_blank\"><img src=\"images/icon-download-02.png\" align=\"absmiddle\" style=\"margin-right: 5px;\"><span>".$library[libr_c_title]."</span></a></span><br>";
            echo "<br>";
        }
    }       
}

I have tested the query in PHPMyAdmin and I get a result however when running the function in my page it only displays the ‘No Related Links’ statement any ideas anyone?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-27T16:28:22+00:00Added an answer on May 27, 2026 at 4:28 pm

    Here’s the fixed code. 🙂 The problem was that you used mysql_query on a Resource (the first mysql_query), and that will give 0 rows, or an exception..

    function getFiles()
    {
        $solnid = $_GET['id'];
        $result = mysql_query("SELECT * FROM library WHERE libr_solutionId = '$solnid' AND libr_deleted IS NULL") or die(mysql_error());
        if (mysql_num_rows($result)==0) {
            echo "<br>No Related Links";
        } else {
            while($library = mysql_fetch_assoc($result)) {
                echo "<span style=\"margin-bottom: 5px;\"><a href=\"Solutions/image/".$library['libr_solutionref']."/".$library['libr_filename']."\" target=\"_blank\"><img src=\"images/icon-download-02.png\" align=\"absmiddle\" style=\"margin-right: 5px;\"><span>".$library['libr_c_title']."</span></a></span><br>";
                echo "<br>";
            }
        }       
    }
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a PHP file with one simple echo function: echo 'アクセスは撥ねりません。'; but when
I have a php file that receives data from mySQL table. The mySQL table
I have a problem. I want to send 3-4 variables from a PHP File
I have a PHP file which will return something like <div id=title>Add Us On
I have a PHP file that contains a lot of if and else statements
I have a php file somejson.php that echos a json encoded array {jsonone:first json,jsontwo:second
i have one php file which process adding of record in Database fro array.
I have a php file that contains a form (which contains 2 input boxes
I have a PHP file that I need it to detect it's directory it's
I have a php file which has a require_once Statement (?) this file is

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.