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Home/ Questions/Q 7905003
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T10:17:44+00:00 2026-06-03T10:17:44+00:00

I have a php file that contains an array $myArray . <?php $myArray =

  • 0

I have a php file that contains an array $myArray.

<?php 
$myArray = array(
  'key1'=>'value1',
  'key2'=>'value2',
);
?>

I need to read the value of key1 from that array. Is there a way to directly read key1, without including the whole file? Right now I’m using include like this.

$includedArray = include('/path/to/myArray.php');

but this is creating a problem for me, because even though I include it under a new name $includedArray, it still recognizes the old name $myArray which causes naming conflicts.

To solve this problem, I would have changed the included array from a named array ($myArray) to an un-named array, but I can’t make changes to the included files. So is there a way to either:

  • include the file containing the named array, but have it completely forget the original name ($myArray), and have it use ONLY the new name I give it ($includedArray)?

  • or is there a way to simply read 1 key from the array without including the whole file?

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  1. Editorial Team
    Editorial Team
    2026-06-03T10:17:45+00:00Added an answer on June 3, 2026 at 10:17 am

    Then copy the array to another variable and unset the original array?

    path/to/myNewArray.php:

    return call_user_func(function() {
      include "/path/to/myArray.php";
      return $myArray;
    });
    
    /*
    if (isset($myArray)) {
      $tmpMyArray = $myArray; // storing the $myArray if defined
    }
    
    $includedArray = $myArray;
    unset($myArray);
    if (isset($tmpMyArray)) {
      $myArray = $tmpMyArray; // restoring the previous $myArray
    }
    */
    

    usage:

    $whatEver = include("/path/to/myNewArray.php"); // no interference now
    
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