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Home/ Questions/Q 7655623
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Editorial Team
  • 0
Editorial Team
Asked: May 31, 20262026-05-31T12:33:35+00:00 2026-05-31T12:33:35+00:00

I have a php file which connects to a MySql db and read the

  • 0

I have a php file which connects to a MySql db and read the last entry from a specific table. What I am trying to do, is to display(echo) the last entry from the table using a JavaScript popup box into the external html file
Below I have the code for the PHP file (which is working fine) and the html one but unfortunately I can’t figure out how to pass the PHP variable to JavaScript function.

Many thanks in advance.

The php file would be this one:

    <?php

    // 1. Create a database connection
    $connection = mysql_connect("localhost","root","password"); 
    if (!$connection) {
        die("Database connection failed: " . mysql_error());
    }

    // 2. Select database to use 
    $db_select = mysql_select_db("manage_projects",$connection);
    if (!$db_select) {
        die("Database selection failed: " . mysql_error());
    }

    // 3. Perform database query
    $result = mysql_query("SELECT survey_desc FROM subjects ORDER BY id DESC LIMIT 0,1", $connection);
    if (!$result) {
        die("Database query failed: " . mysql_error());
    }

    // 4. Use returned data
    while ($row = mysql_fetch_array($result)) {
        echo $row["survey_desc"]."<br />";
    }

    // 4.1 Alternative way to use returned data
    /* $row = mysql_fetch_array($result);
    echo $row["survey_desc"]."<br />";
    */

    // 5. Close connection
    mysql_close($connection);
?>

The html file:

    <html>
<head>
<script type="text/javascript src="myscript.php"">

    //if clicked Yes open new page if Cancel stay on the page 
    function popup(){
    var r=confirm("echo the php query here");
        if (r==true)
            {
            window.location = "http://example.com";
            }       
}
</script>
</head>
<body onload ="popup()">

</body>
</html>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T12:33:37+00:00Added an answer on May 31, 2026 at 12:33 pm
    <head>
    <script type="text/javascript">
    function popup(){
        var xhr=null;
    
        if (window.XMLHttpRequest) { 
            xhr = new XMLHttpRequest();
        }
        else if (window.ActiveXObject) {
            xhr = new ActiveXObject("Microsoft.XMLHTTP");
        }
        xhr.onreadystatechange = function() {
          if(xhr.readyState == 4){ alert_ajax(xhr); }
         }
        xhr.open("GET", "myscript.php", true);
        xhr.send(null);
    }
    function alert_ajax(xhr){
       var docAjax= xhr.responseText;
       r=confirm(docAjax);
    
            if (r==true)
                {
                    window.location = "http://example.com";
                }
    }
    </script>
    </head>
    
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