Home/ Questions/Q 6674559
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-26T03:45:37+00:00

I have a php form but everytime I open up the php document it

  • 0

I have a php form but everytime I open up the php document it is on, I keep getting these php notice errors:

Notice: Undefined index: sessionid in /web/stud/u0867587/MOBILEPHP/exam_interface.php on line 37

Notice: Undefined index: moduleid in /web/stud/u0867587/MOBILEPHP/exam_interface.php on line 38

Notice: Undefined index: teacherid in /web/stud/u0867587/MOBILEPHP/exam_interface.php on line 39

Notice: Undefined index: studentid in /web/stud/u0867587/MOBILEPHP/exam_interface.php on line 40

Notice: Undefined index: grade in /web/stud/u0867587/MOBILEPHP/exam_interface.php on line 41

When I click on the submit button the notices go away but what do I need to do so that when I open up the php document, there are no notice errors on undefined index?

Below is the coding:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>

<title>Exam Interface</title>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
</head>
<body>

<form action="exam_interface.php" method="post" name="sessionform">        <!-- This will post the form to its own page"-->
<p>Session ID: <input type="text" name="sessionid" /></p>      <!-- Enter Session Id here-->
<p>Module Number: <input type="text" name="moduleid" /></p>      <!-- Enter Module Id here-->
<p>Teacher Username: <input type="text" name="teacherid" /></p>      <!-- Enter Teacher here-->
<p>Student Username: <input type="text" name="studentid" /></p>      <!-- Enter User Id here-->
<p>Grade: <input type="text" name="grade" /></p>      <!-- Enter Grade here-->
<p>Order Results By: <select name="order">
<option name="noorder">Don't Order Results</option>
<option name="ordersessionid">Session ID</option>
<option name="ordermoduleid">Module Number</option>
<option name="orderteacherid">Teacher Username</option>
<option name="orderstudentid">Student Username</option>
<option name="ordergrade">Grade</option>
</select>
<p><input type="submit" value="Submit" /></p>
</form>

<?php

$username="u0867587";
$password="xxxxxxx";
$database="mobile_app";

mysql_connect('localhost',$username,$password);

@mysql_select_db($database) or die("Unable to select database");

$sessionid = $_POST['sessionid'];
$moduleid = $_POST['moduleid'];
$teacherid = $_POST['teacherid'];
$studentid = $_POST['studentid'];
$grade = $_POST['grade'];

$result = mysql_query("SELECT * FROM Module m INNER JOIN Session s ON m.ModuleId = s.ModuleId JOIN Grade_Report gr ON s.SessionId = gr.SessionId JOIN Student st ON gr.StudentId = st.StudentId WHERE ('$sessionid' = '' OR gr.SessionId = '$sessionid') AND ('$moduleid' = '' OR m.ModuleId = '$moduleid') AND ('$teacherid' = '' OR s.TeacherId = '$teacherid') AND ('$studentid' = '' OR gr.StudentId = '$studentid') AND ('$grade' = '' OR gr.Grade = '$grade')");

$num=mysql_numrows($result);    

echo "<table border='1'>
<tr>
<th>Student Id</th>
<th>Forename</th>
<th>Session Id</th>
<th>Grade</th>
<th>Mark</th>
<th>Module</th>
<th>Teacher</th>
</tr>";

while ($row = mysql_fetch_array($result)){

 echo "<tr>";
  echo "<td>" . $row['StudentId'] . "</td>";
  echo "<td>" . $row['Forename'] . "</td>";
  echo "<td>" . $row['SessionId'] . "</td>";
  echo "<td>" . $row['Grade'] . "</td>";
  echo "<td>" . $row['Mark'] . "</td>";
  echo "<td>" . $row['ModuleName'] . "</td>";
  echo "<td>" . $row['TeacherId'] . "</td>";
  echo "</tr>";
}

echo "</table>";

mysql_close();


 ?>

</body>
</html>
Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    That is because the form hasn’t posted yet, and these values are empty. Replace with something like:

    $sessionid = isset($_POST['sessionid']) ? $_POST['sessionid'] : "";
$moduleid = isset($_POST['moduleid']) ? $_POST['moduleid'] : "";
$teacherid = isset($_POST['teacherid']) ? $_POST['teacherid'] : "";
$studentid = isset($_POST['studentid']) ? $_POST['studentid'] : "";
$grade = isset($_POST['grade']) ? $_POST['grade'] : NULL;

    And these must be sanitized before used in a database query, to protect your application from SQL injection attacks.

    $sessionid = mysql_real_escape_string($sessionid);
$moduleid = mysql_real_escape_string($moduleid);
$teacherid = mysql_real_escape_string($teacherid);
$studentid = mysql_real_escape_string($studentid);
$grade = mysql_real_escape_string($grade);

    It is highly advisable to remove the @ from your database calls, as it hides error messages that may result from those calls. Instead, use ini_set("display_errors", 0); to avoid errors showing onscreen in your production code.

    // Remove the @
@mysql_select_db(...)
    • 0