Question

I have a PHP/MySQL date formatting problem. Here, i create the date variables:

$checkDate = date("d/m/y H:i", time());
$datestrto = strtotime($checkDate); 

Then i insert it to a mysql table with the column Datatype of bigint.

When i then, later on, when i need to echo the date, i use this code:

echo '<td>'.date("d/m/y H:i",$row['f_uploaded_date']).'</td>';

But istead of echo’ing the date in the format D/M/Y H:i, it echo’es the date in the format of m/d/y H:i.
Can anyone explain why this is happening, and how to fix it?

Thank you in advance,
Adam

Answer 1

When you insert it into the MySQL table do it like this:

INSERT INTO yourtable(something,somedate) VALUES('something',str_to_date('".$checkDate."','%d/%m/%y %H:%i'))

and when you pull it out from MySQL then do it like this:

SELECT *,date_format(somedate,'%D/%M/%Y %H:%i') as formateddate from yourtable

then in php you use:

$row['formateddate']

Hope it helps you 🙂

EDIT:
The complete code:

$ddate = date("d/m/y H:i", time()); 
$sql = "INSERT INTO files (rowID, file, mimetype, data, uploaded_by, uploaded_date, size, times_downloaded, description) VALUES (NULL, '$fileName', '$fileType', '$content', '$user', str_to_date('".$ddate."','%d/%m/%y %H:%i'), $fileSize, 0, '$description')";