Question

I have a PHP script that calls a bash screen using exec and passes some variables via -f= and -d=

I am just wondering how can I access these in bash? For example I would call

scaleImage.sh -f=filename -d=directoryname

And I want to get those variables in scaleImage.sh

Answer 1

Inside the script you can access those strings via positional parameters. For example:

echo $1
echo $2

would output

-f=filename
-d=directoryname

You could use brace expansion or word splitting to break those apart.

See also the section on getopts in man bash for another way to process options and arguments. Your command line would probably need to look like this if you use getopts:

scaleImage.sh -f filename -d directoryname