Question

I have a PHP script that inserts rows into a table based on selected rows from a MySQL array.

the code to insert the rows into the new table is:

$sql="insert into loaddetails (CaseNo,GrossMass,CaseStatus,Customer)
select `case no`,`gross mass`,`case status`, customer from
availablestock where `case no` = '$val'";

I want to assign all the inserted rows the same ID so that multiple stock items share the same LoadID.

How can I modify my code to do this so all the inserted records share the same ID and the ID is unique to the load.

I thought I could use the code below to get the max id and increment it by one

SELECT max(loadid)+1 from loaddetails

How can I acheive this? I realise my PHP code is not perfect but it is functional, I just need to add the functionality to allow for the rows to be inserted with a common ID to produce a result as below:

Thanks in advance for the assistance.

Regards,
Ryan Smith

Complete code is:

<?php
    mysql_connect("localhost", "user", "password")or die("cannot connect");    
    mysql_select_db("databasename")or die("cannot select DB");
    $sql="SELECT `case no`,`customer`,`gross mass`, `case status` from availablestock where transporttypename= 'localpmb'";
    $result=mysql_query($sql);
    $count=mysql_num_rows($result);
?>
<table border=1>
    <tr>
        <td>
            <form name="form1" method="post">
                <table>
                    <tr>
                        <td>#</td>
                        <td>Case Number</td>
                        <td>Customer</td>    
                        <td>Weight</td> 
                        <td>Status</td> 
                    </tr>
<?php
    while($rows=mysql_fetch_array($result)){
?>
                    <tr>
                        <td><input type="checkbox" name=check[]  value="<?php echo $rows['case no']; ?>"></td>
                        <td><?php echo $rows['case no']; ?></td>
                        <td><?php echo $rows['customer']; ?></td>
                        <td><?php echo $rows['gross mass']; ?></td>
                        <td><?php echo $rows['case status']; ?></td>
                    </tr>                                   

<?php
    }
?>
                    <tr>
                        <td><input name="planlocalpmb" type="submit" id="planlocalpmb" value="planlocalpmb"></td>
                    </tr>
                    <?php



                            $check=$_POST['check'];

                        if($_REQUEST['planlocalpmb']=='planlocalpmb'){
 {
                            $sql="insert into loaddetails (CaseNo,GrossMass,CaseStatus,Customer) select `case no`,`gross mass`,`case status`, customer from availablestock where `case no` = '$val'";

                            foreach($check as $key=>$value)
                            {
                            $sql="insert into loaddetails (CaseNo,GrossMass,CaseStatus,Customer) select `case no`,`gross mass`,`case status`, customer from availablestock where `case no` = '$value'";
                            $final=mysql_query($sql);
                            if($final)
                            {
                            echo "<meta http-equiv=\"refresh\" content=\"0;URL=php.php\">";
                            }                                            } 
                                }
                                }
                    // Check if delete button active, start this



// if successful redirect to php.php

mysql_close();
?>
</table>
</form>
</td>
</tr>
</table>

Answer 1

INSERT INTO loaddetails (LoadID, CaseNo, GrossMass, CaseStatus, Customer)
SELECT (SELECT MAX(loadid)+1 FROM loaddetails) LoadID, CaseNo, GrossMass, CaseStatus, Customer
FROM availablestock WHERE CaseNo = '$val'

Make sure LoadID has an index!

You may need to lock the table first. I’m not sure.

I didn’t check the rest of your code, but I do notice you have an SQL Injection vulnerability there.